Half-life: Difference between revisions
imported>Mark Widmer m (→Mathematics: Changed t to lowercase for time.) |
imported>Mark Widmer (Added note about approximating ln(2) as 0.693) |
||
Line 2: | Line 2: | ||
{{dambigbox|decomposition|Half-life}} | {{dambigbox|decomposition|Half-life}} | ||
For any reactant subject to first-order decomposition, the amount of time needed for one half of the substance to decay is referred to as the '''half-life''' of that compound. | For any reactant subject to first-order decomposition, the amount of time needed for one half of the substance to decay is referred to as the '''half-life''' of that compound. Although the term is often associated with [[radioactive decay]], it also applies equally to chemical decomposition, such as the decomposition of [[azomethane]] (CH<sub>3</sub>N=NCH<sub>3</sub>) into methane and nitrogen gas. Many compounds decay so slowly that it is impractical to wait for half of the material to decay to determine the half-life. In such cases, a convenient fact is that the half-life is 693 times the amount of time required for 0.1% of the substance to decay. Using the value of the half-life of a compound, one can predict both future and past quantities. | ||
Note: The approximation <math> \ \ln(2) \approx 0.693 \ </math> is used in this article. | |||
== Mathematics == | == Mathematics == | ||
The future [[concentration]] of a substance, ''C''<sub>1</sub>, after some passage of time <math>\Delta t</math>, can easily be calculated if the present concentration | The future [[concentration]] of a substance, ''C''<sub>1</sub>, after some passage of time <math>\Delta t</math>, can easily be calculated if the present concentration ''C''<sub>0</sub> and the half-life ''t<sub>h</sub>'' are known: | ||
:<math>C_1 = C_0 \left(\frac{1}{2}\right)^\frac{\Delta t}{t_h}</math> | :<math>C_1 = C_0 \left(\frac{1}{2}\right)^\frac{\Delta t}{t_h}</math> | ||
For a reaction is the first-order for a particular reactant | For a reaction is the first-order for a particular reactant A, and first-order overall, the chemical rate constant for the reaction ''k'' is related to the half-life by this equation: | ||
:<math>t_h = \frac{0.693}{k}</math> | :<math>t_h = \frac{0.693}{k}</math> |
Revision as of 15:59, 2 December 2021
For any reactant subject to first-order decomposition, the amount of time needed for one half of the substance to decay is referred to as the half-life of that compound. Although the term is often associated with radioactive decay, it also applies equally to chemical decomposition, such as the decomposition of azomethane (CH3N=NCH3) into methane and nitrogen gas. Many compounds decay so slowly that it is impractical to wait for half of the material to decay to determine the half-life. In such cases, a convenient fact is that the half-life is 693 times the amount of time required for 0.1% of the substance to decay. Using the value of the half-life of a compound, one can predict both future and past quantities.
Note: The approximation is used in this article.
Mathematics
The future concentration of a substance, C1, after some passage of time , can easily be calculated if the present concentration C0 and the half-life th are known:
For a reaction is the first-order for a particular reactant A, and first-order overall, the chemical rate constant for the reaction k is related to the half-life by this equation:
Average Lifetime
For a substance undergoing exponential decay, the average lifetime tavg of the substance is related to the half-life via the equation
- .
The average lifetime arises when using the number e, rather than 1/2, as the base value in an exponential decay equation: