User:Dan Nessett/Sandboxes/Sandbox 4: Difference between revisions

Latest revision as of 02:39, 22 November 2023

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$\pi ={\frac {3}{4}}{\sqrt {3}}+24\int _{0}^{1/4}{{\sqrt {x-x^{2}}}dx}$

Test.

Another Test

Revision as of 13:50, 2 January 2012 (view source) imported>Dan Nessett (Test edit function) ← Older edit		Latest revision as of 02:39, 22 November 2023 (view source) Inactive User Bot (talk \| contribs) No edit summary
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	<math>\pi=\frac{3}{4} \sqrt{3}+24 \int_0^{1/4}{\sqrt{x-x^2}dx}</math>		<math>\pi=\frac{3}{4} \sqrt{3}+24 \int_0^{1/4}{\sqrt{x-x^2}dx}</math>