User:Dan Nessett/Sandboxes/Sandbox 4: Difference between revisions

Revision as of 11:17, 26 January 2011

$\pi ={\frac {3}{4}}{\sqrt {3}}+24\int _{0}^{1/4}{{\sqrt {x-x^{2}}}dx}$

$\pi ={\frac {4}{3}}{\sqrt {3}}+24\int _{0}^{1/4}{{\sqrt {x-x^{2}}}dx}$

Revision as of 09:58, 9 August 2010 (view source) imported>Dan Nessett No edit summary ← Older edit		Revision as of 11:17, 26 January 2011 (view source) imported>Dan Nessett No edit summary Newer edit →
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	<math>\pi=\frac{3}{4} \sqrt{3}+24 \int_0^{1/4}{\sqrt{x-x^2}dx}</math>		<math>\pi=\frac{3}{4} \sqrt{3}+24 \int_0^{1/4}{\sqrt{x-x^2}dx}</math>

			<math>\pi=\frac{4}{3} \sqrt{3}+24 \int_0^{1/4}{\sqrt{x-x^2}dx}</math>